Bengaluru, Jan 19 (SocialNews.XYZ) India vice-captain Rohit Sharma became the third fastest batsman to reach 9,000 ODI runs during the series deciding third and final game against Australia here on Sunday.
Rohit needed four runs to get to the landmark and the senior India opener got to it in the final ball of the first over of India's innings to sit behind skipper Virat Kohli and South Africa's AB de Villiers.
Kohli achieved the feat in 194 innings and he is followed by de Villiers (205 innings).
Rohit (216 innings) beat batting greats Sourav Ganguly (228 innings), Sachin Tendulkar (235 innings) and Brian Lara 239 innings) to the feat.
The series is locked 1-1 and here the Aussies rode Steve Smith's 131 to post 286/9 in 50 overs after winning the toss and electing to bat first.
India, in reply, opener with K.L. Rahul and Rohit after Shikhar Dhawan had to be taken for an x-ray. Dhawan was taken off the field after he hurt his left shoulder in the series-deciding tie after he dived to save an Aaron Finch shot in the cover region before hurting his left shoulder in the fifth over.
Source: IANS
About Gopi
Gopi Adusumilli is a Programmer. He is the editor of SocialNews.XYZ and President of AGK Fire Inc.
He enjoys designing websites, developing mobile applications and publishing news articles on current events from various authenticated news sources.
When it comes to writing he likes to write about current world politics and Indian Movies. His future plans include developing SocialNews.XYZ into a News website that has no bias or judgment towards any.
He can be reached at gopi@socialnews.xyz